Amateur Extra › E8 Signals and Emissions › E8C07
E8C07
What is the bandwidth of a 4,800-Hz frequency shift, 9,600-baud ASCII FM transmission?
Pick an answer to check it.
Answer: A. 15.36 kHz
Bandwidth = (K x shift) + baud rate, with K = 1.2. BW = 1.2 x 4800 + 9600 = 5760 + 9600 = 15,360 Hz = 15.36 kHz.
Tip: BW = 1.2 x shift + baud.